Square root

>>9127527
>>>/g/etthefuckout

File: 1358714884213.gif (350KB, 500x344px) Image search: [Google]

350KB, 500x344px

>a square root method
>Copyright Armando

>mexican coding

[math] \displaystyle
\sqrt {x^2} \ne \pm x, \quad \sqrt {x^2} = \left | x \right |
\\
|x| =
\begin{cases}
\;\;\; x & ,x \geq 0 \\
-x & ,x < 0
\end{cases}
[/math]

>>9127737
This is correct.

>>9127527
use a recursive binary search so that ita n log n

Your code can be simplified:
Input n
Print n and n

>Copyright © 2017 Armando.

>Copyright © 2017 Armandillo.

>>9127527
>Armando
lol how much money do you want for me to license your code?

>>9127537
>>9127542
>>9127717
How about we see your C implementation of square root?

>>9127527
I know next to nothing about C but I can tell you're over-engineering.

Here you go.

[code]
#include <stdio.h>

int main(void)
{
int n = 144;
int i;
for (i = 1; i <= n/2; ++i)
if (i*i == n) printf("sqrt(%d) = %d\n", n, i);
}
[/code]

>>9128573
sqrt()

Read C spec, fix the width of your variables or the shift. Anyway, use sqrt from math.h because you won't outperform it on most architectures and it's portable.

>>9127527
Stop being retarded and use Scheme instead. It works and is much more beautiful.

(define (squareroot x)
(define (iteration currentvalue iterationsleft)
(if (= iterationsleft 0)
currentvalue
(iteration (/ (+ currentvalue (/ x currentvalue)) 2) (- iterationsleft 1))))
(iteration 1 10))

>>9128593
This. Or use the power function to 0.5.

>>9127542
>has never coded in his life

>>9128720
these guys too:
>>9128317
>>9128479
>>9128565

>>9128720
Yeah it's auto generated. Still looks retarded.

>>9127527
>printf("raiz(%d)=%d",n,n);
>n
and another
>n

>>9127527
>Xcode

real men use vim and the command line

>>9128918
well spotted

There are also some short vs. int gotchas. Make everything int for simplicity.

>>9128592
I dont know C, but ive been learning python. Do you need to import a math library to use? In python you have to import math to use sqrt()

>>9128722
cool story bro

>>9128954
http://lmgtfy.com/?q=c+sqrt