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Gravel is being dumped from a conveyor belt at a rate of 50 {\rm ft}^3{\rm /min}. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. How fast is the height of the pile increasing when the pile is 16 ft high?
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edit : its 50 ft^3/min
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use the formula for volume a of cone, take derivative and set equal to defined constant, use implicit differentiation to get the height from there, which of course is a function of time and thus can be differentiated
either that, or could actually read your fucking calculus textbook
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>>8480218
Height/Volume * Volume/Time =Height/Time
Volume= 1/3*pi*1/4*Height^3
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>base diameter and height are always the same
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V=pi(2r^3/3)
V'=pi2r^2r'
25/64pi=r'
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>>8480232
I believe this is differential equations not calculus.
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>>8480506
>I believe this is differential equations
Well you're wrong
Faggot
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>>8480506
related rates are taught in calc 1 here
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>>8480506
In America you do this in calc 1, where do you live
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>>8480506
Related rates are calc 1
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>>8481248
>first/second reactions
first/second order reactions
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>>8480218
Shouldnt the gravel be forming a pile with constant angles that's slowly gaining in volume?
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