Would anyone be able to shed some light on the method for how one would go about doing this?
>>55152
9k=3+k
>>55152
The function is defined in two parts. In order to make it continuous, you just have to make the two parts meet.
They split in x=3.
So, in x=3, the two parts need to have the same value.
Which means that:
k*32=3+k
Which leads to:
k=3/8
Thank you