Narrow corner problem

>>379157
>This time
Sounds like you directly copy-pasted this from somewhere.

So let's say your object just barely fits. You can rotate+slide the ends up and down to make a variable-shape triangle touching the corner, without breaking the top wall - which is what would happen if the object was too long. You can do one where the back end creates a 30-degree angle with the wall (In fact, I think you'd have to do this one in real life).

On Side A you have a standard 30-60-90 triangle, where Side A = 2*(2m) = 4m. For Side B, we make another right triangle by creating an imaginary line connecting the 2 diagonal walls. This actually creates a "middle" triangle, and not only that, but another 30-60-90 triangle - but this time, the hypotenuse is 2. Our yellow line is 2/2 = 1m (good reminder that diagrams aren't always to scale). So with that knowledge in mind, we look at our 3rd triangle (Side B as a hypotenuse) and determine that Side B's length is 1*2 = 2m. Not sure if there was a simpler way to do this, but 6m is my result.

File: corner.png (11KB, 1152x648px) Image search: [Google]

11KB, 1152x648px

>>379225
Wrong pic.

File: Untitled.png (26KB, 640x400px) Image search: [Google]

26KB, 640x400px

>>379228
>>379225
Here's a more properly proportioned version of the diagram, using GIMP for accurate angles. I kinda measured the pixels and it seems that the red line is about 3x as long as the 2m gap, which corresponds with my answer. However, I Googled and see people using advanced calculus to handle a similar problem, which leads me to think my answer may be incorrect.