help me with my hw

>>375529
Your functions are:
y=(10-x)/6
y=(x+6)^.5
For c, you'd find the point where the straight-line function goes to 0. As for a and b, well, you already have those which implies you know f(x) and g(x) already.

For h(y), we have to think "sideways" and construct the equations in terms of y instead. So it becomes
x = 10 - 6y
x = y^2 - 6
And if you subtract the "bottom" aka left-side bound from the top you get
h(y) = 10-6y-y^2-6 = 4 - 6y - y^2
Alpha is of course 0, and beta is the point where the 2 graphs intersect. You can go back to your previous equations and plug in x=-2 for this.

said those were wrong

>>375552
>4-6y-y^2
Oops should be 16, not 4.

>>375565
>said those were wrong
Could you be more specific? I know the last function had a small error, but
1) You should've caught that due to my explanation, and
2) Nothing else I said is inaccurate. I checked it all via wolfram before I posted.

File: Capture.png (55KB, 1911x502px) Image search: [Google]

55KB, 1911x502px

>>375574
Well that's embarrassing. It seems that despite my explanation, you aren't really understanding how this works, so I recommend going to a tutor/TA/etc. for some real help. You should start by graphing the functions to understand what's happening.

"Zamorak", I'm not going to spell out your error here, but if you look at the diagram of these functions you should see your critical error.