Any physics teachers here?

>>356845
draw a goddamn force diagram of the object
>constant velocity
what does that tell you?

>>356850
No you don't understand, I drew the diagram and I know the remaining force needs to add up with the other two to get 0N cos the object isn't moving and these are my calculations:

75sin150= 37.5

75cos150= -64.95

-64.95+60= -4,95N(x-axis)

F3 + -4.95 + 37.5 = 0N

F3= -(F1 + F2)

= 4,95+ 37.5

inverse tan of 37.5/4.85= 82.63 degrees

which is NOT one of the multiple choice answers and i'm panicking because I have no lecturers to help because correspondence course

Please tell me what is wrong with my calculations or line of thought.

>>356897
>F3= -(F1 + F2)
kinda-sorta true
>F3 + -4.95 + 37.5 = 0N
wrong
4.95N is the x-axis component of F3
37.5N is the y-axis component
you can't add these numbers directly
these forces are not in the same direction
but how would you find the magnitude of the force with these components?

you fucked up the signs as well
when doing the force balance, split it into components x and y
e.g.
>F1ₓ + F2ₓ + F3ₓ = Fₙₑₜ ₓ
go ahead and find F3x and F3y, then report back

>inverse tan of 37.5/4.85= 82.63 degrees
reference angles, my lad
your answer looks sorta right, but I think you don't know what this number actually means
so draw in F3 and get its angle
>measured clockwise from the x-axis

>>356845
>>356911
The problem is that if F3 needs 4.95N to the left, none of OP's multiple choice options make sense. Going clockwise from +x, everything between 90 and 270 would have a negative x component.

>>356951
huh, you're right. answer should be quadrant IV. question's broke.