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Assume you have 3 tries.
Each try gives you a 3% chance of winning.
You must win twice.
What are the odds?
It's .03*.03, correct?
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>>349338
do you have to win at least twice or exactly twice?
are you allowed to win three times?
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>>349343
At least twice.
You can win three times.
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This is a binomial distribution, so there's a formula you could use for that. I can't remember the formula off the top of my head and am too lazy to look it up, so I'll just calculate the odds manually:
.03*.03*.97*3 + .03^3 = .002646
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>>349346
>It's .03*.03, correct?
wrong
that would be "two wins in two tries"
explanation of anon's answer:
how many ways can you end up with two wins?
win/win/lose = 0.03*0.03*0.97
win/lose/win = 0.03*0.97*0.03
lose/win/win = 0.97*0.03*0.03
how many ways can you win three times?
win/win/win = 0.03*0.03*0.03
those chances are all added together
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