Do my homework :<

Find the market area
Pls :<

>>>/global/rules/2

>>338283
Im 18

>>338289
Proof

You have two equations:
y=2x (a)
y=x^2+1.5 (b)
Integrating these equations creates (where c is an unknown constant):
y=x^2+c (c) - integrated from (a)
y=((x^3)/3)+1.5x+c (d) - integrated from (b)
You did you graphing wrong, there is no intersection between these two equations. Between the boundaries of x=2 and x=4, the equation x^2+1.5 is always larger than the equation 2x, so this is simple subtraction.
Since the unknown constant doesn't matter here, let's find the area under both equations.
For equations (c) and (d), turn them into functions (just replace y with f(x)). Now, for (c) and (d), find f(4)-f(2). If you have no time, here's the working out.
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(e): (4^2)-(2^2) = 16-4 = 12 (for (c), f(4) - f(2))
(f): (((4^3)/3)+1.5(4))-(((2^3)/3)+1.5(2)) = ((64/3)+6)-((8/3)+3) = 56/3+3 = 65/3 (for (d), f(4) - f(2))
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Since equation (b) is always larger than equation (a), all you have to do is do (f)-(e). Convert 12 to thirds for easier subtraction.
(65/3) - 12 = (65/3) - (36/3) = 29/3
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Also, get a tutor, OP. You're either underage or too stupid to understand Year 12 algebra.