Why doesn't the circuit depicted in the diagram work? I know it has to do something with the use of the voltage divider, but other than that, I don't know.
I wanted the voltage divider to cut the voltage in half, because the lamp runs off of about 4.5V and I was thinking of using a 9V batter later. What would be another simple way to drop down the voltage?
Basically I decided to try and make some logic gates (and eventually an 8-bit adder) out of some components lying around. If it wasn't obvious from my very crude schematic, I only understanding the most basic fundamentals of electronics.
Thanks for the help!
>>338261
> I only understanding
I also only have the most basic understanding of the English language.
doesnt one of those transistors needs have the and emitter and collector reversed/rotaded?
>>338270
I don't think so. Most AND gate diagrams I've seen have the transistors oriented this way.
Plus the AND gate works that way, just without the voltage divider.
oh its to emulate an and gate, i didnt read the thread very well (not even the the title), i thought you wanted to clamp voltages, silly me
>i=v/r
is 1ma enough to light the lamp?
>>338315
no, it needs about 70.
I figured that it wasn't getting enough current, but I don't know why. And I never know where to apply ohm's law, as I said, I don't really have a firm grasp of this stuff. Trying to learn more about this stuff is one of the goals of this project.
So, you need to run the lamp from 4.5V?
Why not to calculate suitable resistor for it, or put two lamps in series?
Also, I would recommend you to learn electronics basics...