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For pic related, if I did x[2n], would the points where x[n] = 1, become n = 0.5, 1, and 1.5?
Is that okay if they are not integer values? For some reason I thought the independent variable of discrete signals had to be an integer value.
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>>336690
The question doesn't really make sense? Maybe because you're saying x[n] instead of f(x), or you're confusing inputs with outputs.
A discrete signal can have any value you want, but the key is that it's not continuous. So you can't say x[1.5] in your example.
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>>336698
y[n] = x[2n]
y[1.5] = x[3]
Does that make sense? Or am I still off?
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>>336702
y[1.5] simply does not exist in your example. Only elemtns of Z can be put in for x.
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>>336709
Is there no transformation for x[2n]?
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>>336702
Alright. It's kinda backwards but I see what you mean.
In this case, y would still be a discrete time signal. Every number N in the set of integers can be mapped to an input for y (N_2 = .5*N_1), so we're still talking about a function defined over a countable set of values - which makes it discrete.
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>>336690
y[n]=x[2n] is just the signal where every other point is skipped.
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