Hi, everyone.
I am kinda stuck on a math exercise, and I'd very much appreciate some help. Here's its instruction:
"A quadratic equation can be written both like 'ax^2 + bx + c = 0', and like 'x^2 + px + q'. Show that the first equation have the roots [First picture]."
First of all, I understand that q = c/a, and that p = b/a. But, when I look at the answer sheet, I follow the solution all the way to the last step, where I'm stuck [Second picture]
All help is appreciated.
Here's the solution given in the answer sheet. I don't understand how the right hand side of the last two equations (from up, downwards) equal each other (._.)
>>331347
You can pull out a 1/2a from the denominator of sqrt(1/(4a^2)).
So you have:
-b/2a + (1/2a * sqrt(shit))
And since they have the same denominator you get:
-b + sqrt(shit) all over 2a
recall that sqrt(a / b) is equal to sqrt(a) / sqrt(b)
also recall that you have to be 18 to post here and this is middle school homework
>>331355
I don't understand what you mean by "pull out" 1/2a from the denominator of sqrt(1/(4a^2))... does it go somewhere or something?
I don't understand how I can just change the discriminant's denominator to 2a just like that.
>>331356
If this is really easy for you then it should be very simple for you to explain it. Yet here you are.
>>331367
i did explain it:
>recall that sqrt(a / b) is equal to sqrt(a) / sqrt(b)
that should be enough to realize what is being done here
picrelated is an even more step-by-step explanation
>>331369
Thank you so much! Now I see it.
I knew coming here was a good idea. Thank you again!