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im now trying to study for my test and i came across this problem on pic related
bar AB weight = 294N
CD cable weight can be ignored
Q weight = 1176N
AD=4m
DB=1m
angle omega = 45ยบ
a)calculate the tension (im translating not sure if its called that way in english) on CD cable b)the vertical and horizontal components of the force that the bar AB receives from the A articulation(not sure again but its the thing on point A)
id appreciate any help in trying to understand the problem and if possible after that someone to correct my mistakes after the initial help
thanks a lot
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fuck i mean theta
anyways the only forces acting are the tension and the 2 weights i guess.
i thnik its the angles that are fucking me up pls give me some tips pls im an autist and i cant go on studying unless i solve this shit
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>>327510
it has been a while
I think you calculate forces vertical to the bar and calculate moment at A
3*Fv(CD) = 2*Fv(BAR) + 4*Fv(Q)
so tension is 294*6
maybe wrong... dunno
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File: 1473248350178.png (26KB, 420x441px) Image search:
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To find the tension you'll just need to calculate the sum of moments about point A. This image shows everything you'll need to figure that out.
Then once you have the tension, you can calculate the sum of forces in the X and Y directions. A_x and A_y will be the only unknowns, so finding them will just be simple addition and subtraction.
>>327513
right idea but wrong numbers
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>>327542
thanks so much. im trying it out now. so i should do something like
sumMa=MQ_y + MBar_y -MT_x
0=1176*cos45*5 + 294*cos45*2.5 - T*4*sin45
which gives me T=1653.75N
is that correct?
gonna start the rest now
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