maths help

pls respond

>>322419

As I see it the solution of the problem is the found angle A.for C=1200
So in that case a would mean to find a function f(x) for which f(x=A) = 0 ? Which in other words you can make as simple as you want as longit contains an angle as variable somewhere?

As I see it you need to look if C(A) is defined in the intervall. Isn't he whole point of the secant method that you do not need to calculate f'(x) but only use the numeric approximation with the differential quotient?

For example making sure the denominators never become 0 in the interval.

>>322419
>a)find a function f(x), for which the solution of f(x)=0, is equivalent to the solution of the problem.

If you want find x such that g(x)=h(x) then you can define a new function f(x)=h(x)-g(x). Then when g(x')==h(x'), what does f(x') equal? When f(x'')==0, what are the values of g(x'') and h(x'')?

>>322439
im not sure, in the teachers pdf it says 1st conditions of divergence:
- f a function 2 times differenciable in [a,b]
- f'(x)!=0 ∀ [a,b]
and it also has f(a).f(b)<0 but it later says that it doesnt need f(a).f(b)<0 because the root doesnt need to be between a and b

>>322442
thanks for the help but im too dumb to understand that

>>322452
convergence not divergence

im going a bit crazy over this shit

every secant method calculator basically shows me that its not possible to find the roots of this piece of shit equation

is my input right? i wonder if thats whats fucking me up, in wolframalpha it seems correct but the graph is really weird

https://www.wolframalpha.com/input/?i=(pi*((300%2Fcos(x))%5E2)*0.8)%2F((pi%2F2)*(14)%5E2*(1%2Bsin(x)-0.5*cos(x)))

>>322505
fucking hell i needed to add -1200 to the end of the function so that the method works

still unsure about the first question though

>>322505

But you're not supposed to find the root for a) I think, but the solution for C(A)=1200

>>322525
yes, and it will give me ~0.1176 rad

which is the root im supposed to find using the secant method with this ((pi)((300/cos(x))2)0.8)/((pi/2)(14)2(1+sin(x)-0.5*cos(x)))-1200

i was being dumb

>>322525
>>322439
>>322442

so if C=z(A)=pi(h/cos(A)...

for a) i could say that z(A)=C is equivalent ti z(A)-C=0 and define f(x) as z(A)-c