Show me how to solve this

>>310114
You can't solve for two variables with just one equation.

>>310114
Gimme a sec

1. 8 is the same as 2^3, so following rules of exponentials 8^x would equal 2^(3x)
2. Rearrange the eqn given in terms of y, i.e y=3x-12
3. Substitute this answer in place of y in the second equation, as everything is now in terms of x the eqn is now solveable. 2^(3x) / 2(3x-12) is the current form.
4. Use the rules of exponentials again, that 2^(a+b) = (2^a)*(2^b)
5. So now it's 2^(3x) / (2^(3x)*2^(-12)) and if you write it out you'll see that the 2^(3x)'s on the top and bottom will cancel
6. This leaves you with 1/(2^(-12)) which of course is identical to 2^12

Hope this makes sense, i'll try to clarify if not or if i messed up somewhere

8^x = 2^(3x)
8^x/2^y = 2^(3x - y) = 2^12

>>310114
this can be solved by a 5th grader in my country.
Where are you from ?
also you need to be 18+ to post on this website.

First,
3x - y = 12, so y = 3x - 12

And
8^x = 2^3x

So we have:
8^x / 2^y = 2^3x / 2^y = 2^(3x - y) = 2^(3x - 3x + 12) = 2^12

done

>>310930
You came to a thread where the answer had already been shown and added a pointless extra step. Why?