Can someone explain to me how we get the e^i(4pi/3) bit in pic related? How do you divide Euler's form by another?
I've tried multiplying by the conjecture, but couldn't get the same result.
Division of exponents is equal to subtracting them
Also, remember that e^i2pi = 1
>>285958
2pi - (4pi/3) = 10pi/3 so that doesn't help
If I say e^i2pi = 1 than it becomes 2[1/(-i4pi/3)] doesn't it?
>>285991
So 1/a^b = a^-b.
Therefore 1/(e^-i(4pi/3)) = e^i(4pi/3).
So by just removing e^i2pi because it's equal to 1 you get the desired result.
8/4 * e^i2pi * e^i4pi/3 = 2 e^i4pi/3
Ask away if I wasn't clear enough.
>>285998
yeah makes total sense, really dumb of me to forget 1/a^b = a^-b
Thanks!