can someone please help me w/ this
find an eq'n of the circle 2x+y+1=0 at the point(2,5) if its center is on the line x+y=9
what do you mean? do you mean the centre is at the point 2,5? then why does it matter that its on the line?
>>271658
2x+y+1=0 is a line not a circle lmao
this post is a mess
>>271778
ot to mention he says "find an equation of the circle"...which he the attempts to define with an equation
sorry my bad i mean find its center tangent on the line 2x+y+1=0 at the point (2,5) if its center is on the line x+y=9
find the eq of the circle tangent to the line 2x+y+1=0 at the point (2,5) if its center is on the line x+y=9
>>271848
To find the equation of a circle, you need the coords of its center and the length of its radius.
This is a worksafe board
exactly, but how, can you show me the solution
>>271881
im still not getting what youre asking. is the circle meeting the line 2x+y+1=0 at only 2,5 and has a centre on the other line?
>>271885
because2x+y+1=0 doesnt contain 2,5
yeah, im confused either, i thought the same thing the first time i encountered the problem, this was just actually a question given to me from a friend
ok let's say those really are the points can you show me the solution?
>>271908
The radius of the circle is a segment who is perpendicular to the line 2x+y+1=0 at the point 2,-5.
And this same radius cross the second line at the point which corresponds to the center of the circle.
You have to think the radius like a vector, and use a scalar product to resolve the equation which will gives you the coords of the center of the radius.
Okay. I guess I'll ask what everyone is thinking about asking...
Sauce on the qt3.14?