Python Help

>>265994

Think about what you're doing with the repetition operator (*). It means "ZERO or MORE". You're basically matching when there are ZERO instances of what you're looking for.

>>265994
Also "\s" is just a stupid way of writing "."

>>265994
Also

if (condition):
__return(true)
return(false)

is an antipattern in any language, not just Python.

Just write

return (condition)

>>266014

\s matches whitespace. The dot matches anything.

>>266008
how can i see if the entire string matches the conditions instead of if a match exists in it

>>266026
It's already doing that, it's just that your regex matches a bunch more whole strings than you intend to.

>>266032
can you tell me how it's matching strings like "asdasdfhasdf" and "2/3"? I've been using an online tool to check and it doesnt work on the tool

>>266043
You need to nail it down with ^ and $.

Go work through regexone.com .

>>266026

You don't understand the repetition operator. It matches ZERO OR MORE. Think about this:

Suppose you're trying to match the letter A and you do:

A*

Now think about what this does. It matches A zero or more times. So it will match in the following instances:

A
AA
B ( it matches once because it found the letter A zero times)

Now you understand what your problem is? Turn the repitition operator from * (zero or more times) to + (one or more times)

File: firefox_2017-02-13_17-13-48.png (11KB, 588x325px) Image search: [Google]

11KB, 588x325px

>>266068

Use this page to test your regular expressions: http://regexpal.com.s3-website-us-east-1.amazonaws.com/

Now you can do this. It will match what you're looking for. Like >>266064 said, you might want to use ^ and $ to match the string exactly.

>>266064
>>266073
^ and $ Worked, thanks