Dividing a polynomial by a binomial

>>264993
It's clearly an identity you brain-dead moron.

File: received_1325763444145501.jpg (27KB, 405x650px) Image search: [Google]

27KB, 405x650px

>>265002

>>264993
x^2-36 = (x+6)(x-6)

So (x^2-36) / (x-6) = x+6

>>264993
I don't see the 1st problem, but I assume it's

(x^2-2x-8)/(x+2)

(x^2-2x-8) = (x-4)(x+2)

(x^2-2x-8)/(x+2) = (x-4)(x+2)/(x+2) = (x-4)

I know (x+6)(x-6)=x^2+6x-6x-36=x^2-36, but the problem isn't working it by distribution, it's to take x^2-36 and divide it by x-6. When I do that following the way I've been taught in the book, I come up with -72 at the end of the division and (x-6)(x-6) as the answer, as shown in the picture. The problem on top was just demonstrating the long division method the book has taught me for dividing trinomials by binomials.

So basically I need to know how to use long division to divide x^2-36 by (x-6).

>>264993
>>265032
>-6x-36
Think again. Have you ever stopped for a while and wondered (((why))) long division works?

You didn't distribute your negative sign during your first step. You just dropped the -6x to the second step instead of subtracting it.

Thus, your second step should have 6x - 36, not -6x - 36, and should divide fine to x + 6.

Its usually a good habit to write out "- (x^2 - 6x)", kinda like to did in your second step, so you don't miss these things.

>>265040
Well aren't I dunderpate. Thank you, anon.