Geometric probability

https://youtu.be/8XXO_QUIN2A?t=5m49s

>>249679
top stuff lad

ta

>>249675
you use the area of the square a*a as the x percent and the circle area pi*r^2 as the 100%

so you can say

a^2/(pi r^2) = x/100

proceed to put the 100 on the left side and bam x is your percentage.

The percentage of the square area will also be the chance to hit this spot.

>>249689
Oh yea forgot to mention, to actually calculate it you need to use r=0.5/√(a^2+a^2)

and choose a random a, it will always be the same result (chance)

you need to do this because this is the radius of the circle considering it equals half the diagonal of the square.

>>249689
because i am bored:
100•[(a^2)/(pi•0.5•√(a^2+a^2))]=x

with a being one:

100•(1/(pi•0.5•√(2)))=x

now calculate it and round it down son

>>249675
This is much simpler if you consider a quarter of the circle.

The area of a quarter of the circle is 0.25(Pi*r^2)= 0.25Pi(r^2)
The quarter of the square forms a triangle, and the area of a triangle is 0.5bh. b=h=r, so the area of that triangle is 0.5(rr)=0.5(r^2)

The ratio of the two is 0.5(r^2)/0.25Pi(r^2)
=0.5/0.25Pi
=2/Pi
~=64%