HELP ME WITH THIS MATH PROBLEM

>>227174
System of equations. Have two variables, x and y, which represent the weights of the two different types of candies.
Say x represents the candy that is $1.08 per kilo, y represents the $3.05 per kilo candy.
As she is getting 24 kilograms of candy, the weights of the two types of candy adds up to 24:
x + y = 24.

Also, as she is getting 24 kilos of candy, and the mixture will be worth $2.64 per kilo, the mixture will cost a total of:
2.64 * 24 = 63.36.

This $63.36 mixture of candies is composed of different weights of candies x and y. Therefore, as candies x and y cost $1.08 and $3.05 per kilo, respectively:
1.08x + 3.05y = 63.36.

So now you have two equations:
x + y = 24
1.08x + 3.05y = 63.36.

Solve.

>>227186
this makes sense... but which method do I used to solve with the two equations left? substitution?

>>227186
actually.. addition/ elimination would work better..

>>227193

Any method will reach to the same answer.

>>227199
I got an answer of .224y = 5.0688
does this seem right?

>>227201
Nope. I assume you haven't taken linear algebra so you don't know row-reduction and echelon forms?

>>227196
what is this in reference to in my post? Addition/elimination works only after you've established which equations you're working with.

>>227202
no I have not. This is part of a bonus question on my assignment... could you maybe show me the first step to approaching x+y = 24
1.09x + 3.05y = 63.36

>>227205
y = 24 - x

>>227203
just me brainstorming/ coming up with possible ways to go about it

>>227206
got x=5

>>227208
Show me your process.

>>227208
>>227210
Wait, my bad, just checked my notes again, that's right.

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2MB, 3264x2448px

>>227210

>>227213
Correct, good job.