Solve this math for me pls

Better pic?

Formula for a cone: πr^2 * (h/3)

So as the circumference is 50 the radius is 15.915

The height of the mound will be 12 as it's 1 metre below the 13m conveyor belt

π * (15.915^2) * (12/3)
π * 253.287 * 4
= 3182.9m^3 of gravel

Convert into cubic centimeters = 3,182,900,000cm^3


What we now need is "Resource A" specified on your sheet, to get the dimensions of the dump truck and figure out how much gravel it will transport at once

File: f4693db2-2307-4692-9224-56b7eadb9241.png (222KB, 540x960px) Image search: [Google]

222KB, 540x960px

Thank you, if I could get this one too. I don't have better pictures cause it's my gf's homework not mine. She's asking me for help

Top section = 5m * 2.35m * 1.2m
= 14.1m^3

Bottom section = (5m * 2.35m * 0.18m) - (5m * 0.17m * 0.18m)
= 1.962m^3

Altogether = 16.062m^3

Truck is 1m shorter, which is 4m. So multiply by 4/5 = 12.8496m^3


add the 2 together for 28.9116m^3 or 28,911,600cm^3 of gravel per trip.


As we want to transport 3,182,900,000cm^3, this takes 111 trips.

A round trip is:
- load truck = 4min
- drive to site = 12min
- positioning = 5min
- unload = 28,911,600 / 650,000, or 44 seconds
- drive back = 12min
- total for a round trip = 33 minutes, 44 seconds

So 111 trips multiplied by 33 minutes and 44 seconds gives you the grand total

111 * 2024 seconds = 224664 seconds / 3744.4 minutes / 62 hours, is how long it takes to transport all the gravel to the building site

>>224631
Oh, my B, it's actually 224,624 as the last unload takes only 4 seconds. Which is 3743.7 minutes or 62 hours.