Hello /wsr/ I have a request. I I need to set up these numbers

Exercise 3)
Let s be the number of squares, p the numer of pentagons and h the number of hegagons.

We know there are 24 signs in the package, so
s+p+h=24
Also the total of all sides is 112, so
4*s+5*p+6*h=112
Finally we also know that there are 10 more squares than pantagons, so
s=10+p
or equivalently
s-p=10
In total or systems of equations is
s+ p+ h= 24
4*s+5*p+6*h= 112
s- p = 10

>>223757
Thank you

All these questions are simple elimination:

Q4.
2L + 2N + 2V + 2E = 114 (1)
E + 2L = 60 (2)
2N + 2E = 78 (3)
L + 2E = 78 (4)

Therefore L = 2N
(2) x 2: 2E + 4L = 120 (5)
(5) - (4): 3L = 42

Therfore L = 14f, N = 7f
E = 60 - 2(14)

Therefore E = 32f

V = 114/2 - 14 - 7 - 32
Therefore V = 4f.