can someone help me with this? answer should be (ln^2)*8/ln16

u=lnx
du=(1/x)dx

sub in to get

integral of udu

integrate that and get (u^2)/2, then sub back to get ln^2(x)/2, I think

>>211964
Keep in mind that this is log base 4, the answer given uses change of base formula having log4(x) = ln(x)/ln(4)

>>211964
i think that works, thanks

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27KB, 908x812px

>>211966
To accompany this, here is my crude work.

>>211968
thank you so much, i had to study for a chem test on tuesday so i didn't get to start on this review until almost the end of the week and my professor only has office hours on m,w,and Thursday so i wasn't able to get many problems done

>>211966
>log4(x) = ln(x)/ln(4)
I knew I was missing something.

>>211971
To be fair, giving you a logarithm that isn't a natural is retarded because most people don't have the change of base formula memorized.

>>211973
yeah the teacher gave a really hard review for the last exam, which turned out to be easy last time, but still don't want to risk not doing a problem.