Would a fellow Anon kindly solve this calculation?
[X] Currently moves 0.05 Units every 0.05 Seconds.
At this speed, [X] covers 72 Units in 90 Seconds.
How many Units per Second does [X] need to cover 72 Units in 600 seconds?
Well, unless the question is misphrased, the way I see it [X] will make 20 'jumps' in one second, covering exactly 1 Unit of distance in 1 second. So it covers 72 Units in 72 seconds. So either it's a trick question or I'm missing some key data here
>>152461
>[X] Currently moves 0.05 Units every 0.05 Seconds.
>At this speed, [X] covers 72 Units in 90 Seconds.
There's a contradiction here. Line 1 indicates a speed of 1 unit per second, line 2 indicates a speed of 0.8 units per second, despite claiming both refer to the same speed.
In any case, 72 units per 600 seconds is 0.12 units per second, by simple division.
>>152461
speed/velocity = (distance traveled) / (time it took).
(there is a difference between speed and velocity, but you don't need to worry about it.)
Think about a speedometer. Speed is in miles (distance) per hour (time).
"divided by" "per" both mean the same thing, division.
What's the distance? 0.05 units.
What's the time it took? 0.05 seconds.
You know what 0.05 units/0.05 seconds is, right?
What's the distance? 78 Units.
What's the time it took? 200 seconds.
78 Units / 200 Seconds = 78/200 units/second.
>>152689
lol, I wrote "speed/velocity" without realizing I was using the / symbol for two different things in the same line of text.
I meant both speed and velocity are defined as distance per time.