Algebra 2, logarithms

e) is log_2((2^5)^2) = log_2(2^(10)) = 10

Just google properties of logarithm and use the fact that logarithm is an injective function.
Also, global rule 2.

File: 13321278_1136847036337533_1588981764_o.jpg (167KB, 1700x716px) Image search: [Google]

167KB, 1700x716px

>>134625
im exactly 18, I got the mèmès to prove it

Ok, so what you must know is that log(a) = log(b) <=> a =b
c) log(x2-1) = log(x-1)
x2 -1 = x-1
(x-1)(x+1) =x-1
x=/=1 as log(0) is impossible
<=> X+1 = 0
<=> x = -1
No solution QED

>>134640
Don't use QED in such way

>>134618
OwO, alguien hispanoparlante dame un abrazo compañero

>>134618

Look up the rules of logarithms online -- there's a bunch you need to memorize and apply.

According to research that we do at our HS math academy where I teach, memorizing the many rules is the most efficient way of learning and becoming comfortable with logarithms conceptually (as opposed to memorizing maybe 4 rules and deriving the rest each time).

Once you see the rules, the answers should come quickly -- just apply them one at a time. For example, when you see the same number in the base of two logarithms, a rule can usually be applied to combine the two.

But again, here, unlike the math you did before, YOU MUST MEMORIZE THE RULES.