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So?

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Thread replies: 78
Thread images: 31

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So?
>>
>>9164204
Is the lower case z the same as the upper-case Z?
>>
>>9164205
Both are same, resize messed up bottom one.
>>
(1-4i)z=10+11i
(1+4i)(1-4i)z=(10+11i)(1+4i)
(1+16)z=10+40i+11i-44
17z=-34+51i
z=-2+3i
>>
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>>9164222
correct
>>
>>9164204
>>9164222
>how to make an anon do your homework by playing on his self esteem and questioning if he fits in
nice, also pathetic
>>
>>9164233
Do you have a more interesting math problem
>>
ITT: gullible idiot completes OP's homework.
>>
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>>9164235
>implying you can't just look it up on wolfram alpha
>>
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>>9164236
>>
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>>9164263
Got any more harder ones, based anon
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>>9164282
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>>9164282
Try proving this one.
>>
>>9164204
Is this the highschooler edition thread?
>>
>>9164291
Looks like it.
>>
>>9164236
>interesting
Do you get excited when doing retarded algebra manipulation? Jesus
>>
>>9164204
https://www.wolframalpha.com/input/?i=(1-4i)z%3D10%2B11i
>>
>>9164204
https://www.wolframalpha.com/input/?i=(1-4i)z%3D10%2B11i
>>
>>9164204
It's exactly:

Z=(10+11i)/(1-4i)
>>
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>>9164290
Maybe I'm understanding this one wrong because I can produce counterexamples
>>
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If you're doing homework for free might as well do mine.
>>
>>9164399
is this a problem in rudin?
>>
>>9164416
not that I'm aware of
>>
>>9164348
You need to review series from the ground up.
>>
>>9164399
I pretty much solved that for you in the other thread.
>>
>>9164348
You're understanding it wrong. It's asking if the SEQUENCE converges, not if the SERIES of the sequence converges. Also, >>9164439
why would he need to review series? I think he just misread or something.
>>
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>>9164289
Done!
>>
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>>9164399
You too, although I'm not sure if its rigorous. Tips appreciated.
>>
>>9164293
My dick gets hard when I FOIL desu
>>
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>Thinly veiled homework thread

I guess I'll post some old problem sets from a class I took 2 years ago. Have fun.
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>>9164689
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>>9164692
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>>9164695
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>>9164698
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>>9164700
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>>9164705
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>>9164708
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>>9164710
>>
Could anon break down Einstein summation Convention for someone whos not able to use or understand it?
>>
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>>9164712
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>>9164714
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>>9164717
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>>9164719
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>>9164723
>>
>>9164282
To be fair,/sci/ is not only for math,but science too.To belong in /sci/ and not /b/ you only should know 10th grade maths like pic related
>>
>>9164204
z = (10+11i)/(1-4i) = (10+11i)*(1+4i)/17 = (-34+51i)/17 = -2 + 3i.
>>
>>9164204
z=(10+11i)/(1-4i)

multiply by complex conjugate of denominator to simplify.

Get 2+3i=z.
>>
>>9165133
Then it should be easy :^)
>>
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>>9164290
Am I just retarded or is this quite simple?
>>
>>9164290
This is just the average. Put the first sequence tail within epsilon and we can put the second within delta as the earlier terms over n approach 0. They converge to the same number.
>>
>>9164659
Reorder your statements. Ideally sentences don't start with "since" as this means you went result->proof. Only do that when the proof is longer than one sentence.
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>>9165667
No, no, no, absolutely not. There is an n in the sum, so you can't distribute it into the sum.
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>>9165651
you dont know how complex numbers work do you
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>>9165651
t. engineers
>>
>>9164241
But that won't give you the step-by-step solution unless you pay for it
>>
>>9164290
a_n = 1 for all n

Then a^bar_n can't converge, right
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>>9166068
Intuitively, it makes sense because you are just taking an average of the more and more terms. It'll just converge to the same thing as the original sequence, but it gets kinda gross to do with rigorous limit proofs.
>>
>>9166072
Oh, I'm stupid, I mixed up n and k
>>
Does anyone else find the standard complex number notation really ugly?
Expressing a number as a + bi usually looks like shit.
The polar notation does look better, even if it's a bit more difficult to use.
[math]re^{i\theta} > a + bi[/math]
>>
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>>9166966
and checked
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>>9164290
Call the limit "a" Given e=epsilon, there is a positive integer M such that |a-a_n|<e/2 when n>M. There is an integer N>M such that 1/n sum_{m=1}^M |a_m| < e/2 when n>N. Etc.
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>>9164282
You dun goofed. 3n-1 became 3n+2 in the next step.
>>
>theoretical comsci MSc student
>can't solve any of this shit
Am I fucked?
>>
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>>9166966
complex numbers can't have a greater-than relationship, anon.
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>>9168005
Uhh yeah they can, in a 2d vector space where radius is the metric
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>>9168009
If you're fine with shit like -5 > 2, I guess.
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>>9167887
I shifted the bottom of the infinite sum from n=1 to n=0 to apply the infinite geometric series formula.
>>
>>9164728
>tfw were in accelerated math class and skipped 2 years
>still didnt leartn this before grade 11

norway is so fucking shit, its education system treats everyone like they're literally retarded. I wish i was home schooled so fucking much as i'd be working wit ayy lmaos by now.
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>>9164712
>>9164719
>>9164725

These are actually pretty spicy
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>>9166053
The mobile app gives a step by step solution. It's only on desktop that you need to pay.
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>>9168020
you can use 1 though
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>>9169409
But I didn't
>>
>>9164713
just read the wikipedia article for that. if you dont understand just remeber to hide the summation sign and sum over the same index. If someone can point out how to use latex on 4chan again i could write up a better example
>>
>>9164204
z = (10 + 11i)/(1-4i) obviously

fucking brainlets, i stg
>>
https://www.wolframalpha.com/input/?i=(1-4i)z+%3D+10%2B11i
>>
If you passed calc 2 you should be able to solve this

That means no wolfram alpha
Thread posts: 78
Thread images: 31


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