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Sup 4chan throw in a good differential equation problem and we'all

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Thread replies: 12
Thread images: 5

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Sup 4chan throw in a good differential equation problem and we'all try to solve it! Ex

dy/dx + 2x/(1-x^2) = 4x

Where -1<x<1
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>>9154041
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>>9154076
Here is my riposte (not OC)
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>>9154041
how can you call that shit a DE it's almost a direct integral
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>>9154079
1.) Naturally, if r depends on m, dy/dx=(1/r)sin^2m dr/dm. Hence, the equation becomes r (sinm + cosm)(1/r)sin^2mdr/dm=r (sinm-cosm).

Thus dr/dm=r*(sinm-cosm)/(sin^2m (sinm+cosm))=-r. Then dr/dm+r=0.

2.) The equation can be rewritten as -x (x^2+y^2)dy/dx=-y(x^2+y^2) since the rest of the equation is equal to zero as per 1.). This becomes cosmsin^2mdr/dm=rsinm which then becomes cosm sinm dr/dm=r.

The equation becomes ln r= 2int csc2m. I don't know how they're getting the equation specified on the problem from this.
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find function's domain
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>>9154041
Sup 4chan, let me type down my homework and pretend it is some challenge problem so that all the retarded cucks can do my work for me.

>>9154076
Spotted a cuck

Anyways. OP please remember that the homework board is >>>/hm/ and people who like to answer to homework threads please remember that the faggot board is >>>/lgbt/
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>>9155059
Do your own homework.
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2+2=? Plox guys help
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>>9155198
fine
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>>9155059
R*+
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>>9155205
I may just be tired, but I kek'd pretty hard.

Just square the equation first then go from there, friend.
Thread posts: 12
Thread images: 5


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