Sup 4chan throw in a good differential equation problem and we'all try to solve it! Ex
dy/dx + 2x/(1-x^2) = 4x
Where -1<x<1
>>9154041
>>9154076
Here is my riposte (not OC)
>>9154041
how can you call that shit a DE it's almost a direct integral
>>9154079
1.) Naturally, if r depends on m, dy/dx=(1/r)sin^2m dr/dm. Hence, the equation becomes r (sinm + cosm)(1/r)sin^2mdr/dm=r (sinm-cosm).
Thus dr/dm=r*(sinm-cosm)/(sin^2m (sinm+cosm))=-r. Then dr/dm+r=0.
2.) The equation can be rewritten as -x (x^2+y^2)dy/dx=-y(x^2+y^2) since the rest of the equation is equal to zero as per 1.). This becomes cosmsin^2mdr/dm=rsinm which then becomes cosm sinm dr/dm=r.
The equation becomes ln r= 2int csc2m. I don't know how they're getting the equation specified on the problem from this.
find function's domain
>>9154041
Sup 4chan, let me type down my homework and pretend it is some challenge problem so that all the retarded cucks can do my work for me.
>>9154076
Spotted a cuck
Anyways. OP please remember that the homework board is >>>/hm/ and people who like to answer to homework threads please remember that the faggot board is >>>/lgbt/
>>9155059
Do your own homework.
2+2=? Plox guys help
>>9155059
R*+
>>9155205
I may just be tired, but I kek'd pretty hard.
Just square the equation first then go from there, friend.