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Triple integrals

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So, basically I am too stupid to understand this damn thing. Basically when I solve the triple integrals and I proceed directly to the coordinate change I get a negative volume. So I had a look at some solved exercises and the dude first solve them using the...strates and wires (okay I have no clue how to call it in English)....and then proceeds to change the domain and pass to a a different coordinate system. So how the fuck should I proceed?
>>
>find min/max values of x
>find bounds for y in terms of x
>find bounds for z in terms of x and y
>???
>Profit
>>
>>9117284
Dude, but that's the sphere equation. How can you do that? Is not a simple domain. That's why I was thinking to integrate it simply in terms of z but if I do it in spherical coordinates it gets crazy
>>
>he thinks he cam just SOLVE triple integrals
They give out fields medals for that OP
>>
-1 <=z <=0 implies that 0<=x^2+y^2 <=3. This means that 0 <=y <=(3-x^2)^(1/2) and 0 <=x <=(3)^(1/2)
>>
>>9117289
>Is not a simple domain.
It's not that hard. A half-circle equation is [math]\sqrt{1\,-\,x^2}[/math]. You can do everything from this and integration by substitution.
Thread posts: 6
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