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WHAT THE FUCK

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Thread replies: 20
Thread images: 6

File: math HELP.png (15KB, 892x428px) Image search: [Google]
math HELP.png
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How the FUCK do I solve this type of problem?

I tried the law of sines, the law of cosines, literally everything but my answers are NOT what the book has

the book has
magnitude = 39.20N
angle = approximately 21.46o

BUT I HAVE NO FUCKING IDEA HOW THEY DERIVED THOSE ANSWERS. The examples in the book don't explain this type of problem at all

Am i missing something? What is going on?
>>
>>9107865
do you even trigonometry?

We are not here to do your homework.

hint: you do have enough information
>>
File: math RAGE.png (30KB, 892x689px) Image search: [Google]
math RAGE.png
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>>9107868
yes I trigonometry

by this logic i do this (pic related)
angle b should be approximately 63.66
so if i do simple triangle math
180o - 35o - 63.66 = 81.34o for the top left angle

therefore, I SHOULD be able to use fucking Law of Cosines to find the answer, BUT MY ANSWER ISNT WHAT THE BOOK FUCKING HAS?!

c^2=25^2+16^2-2(25)(16)(cos(81.34))
c^2=760.54
c=27.57

BUT AS YOU SEE, THATS NOT WHAT THE BOOK HAS

the book has 39N, whereas my calculation is 27

what the FUCK
>>
>>9107865
The book answer is wrong
>>
How about you take a picture of the problem instead of your shitty drawing.
>>
File: WIN_20170815_21_44_25_Pro.jpg (185KB, 1280x720px) Image search: [Google]
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>>9107897
problem 35
>>
>>9107906
Take a non blurry picture you fucking retard.
>>
>>9107906
35° is the angle between F and G homo
>>
File: WIN_20170815_21_49_37_Pro.jpg (169KB, 1280x720px) Image search: [Google]
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>>9107912
there's nothing missing, this information is the exact same information as my OP. i'm not sure what you're looking for here
>>
>>9107918
>add horizontal components together
>add vertical components together
>square the total vertical component, square the total horizontal component, add together, take the square root
>now you have magnitude
>take the arcsine of the vertical over the horizontal components
>now you have the angle
>>
>>9107929
*arctan, not arcsin
>>
>>9107915
>35° is the angle between F and G homo
ARE YOU FUCKING KIDDING ME RIGHT NOW

thank you, i was growing literally insane
>>
Let me spell this out for you:
Let R be the resultant force
Rx = F + G cos(a)
Ry = G sin(a)
|R| = sqrt(Rx^2 + Ry^2)
theta = Arctan(Ry/Rx)
>>
>>9107918
Theta is not needed, and the "x" in your OP is WRONG. Angle between F and G is alpha you idiot.
Sage this shit, please.
>>
>>9107942
literally none of that was in the examples, i just got finished reskimming the chapter for the 5th time

thanks anon you're a godsend
>>
>>9107965
That only works for this specific case. To add two (or more) vectors, you can always break them down into their components and add those.
Rx = F_1 cos (th_1) + F_2 cos (th_2) + ...
Ry = F_1 sin (th_1) + F_2 sin (th_2) + ...
>>
>>9107971
i don't think we're that far into the studies yet, this is general stuff (pre-calc 2)

I recall some Rx talk but we've never had to add 3 or more vectors at once yet. i'll keep that in mind for calc 1 though. cheers anon.
>>
File: 1502847070670.png (49KB, 1360x689px) Image search: [Google]
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>>9107881
>angle b should be approximately 63.66
You can do it with sine/cosine laws, you just have to do it right. None of this approximation bullshit.
>>
>>9107865
sqrt((16+25*cosd(35))^2 + (25*sind(35))^2) = magnitude
arctan((25*sind(35))/(16 + 25*cosd(35))) = x
>>
>>9107881
its 39.19593 N
your book is right, the 39 degrees refers to the angle between the vectors of length 16 and length 25.
Thread posts: 20
Thread images: 6


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