How can i properly calcularé log√ab if given that log a2=m and log b3=n?. In exchange, i will be dumping rare pepes if someone is able to solve it before an hour after this thread is posted
(1/4) m + (1/6) n
log(a^2) = m so log(√a) = log((a^2)^(1/4)) = m/4.
similarly for b
>>9104169
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