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Dumb Question

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Thread replies: 7
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File: C3sZ7foUEAIrggj.jpg (128KB, 1000x1000px) Image search: [Google]
C3sZ7foUEAIrggj.jpg
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What's it called when you want to decompose an integer into only 3 numbers that add up to the original?

Some examples include:

6 -> Only 1,2,3

9 has (1,1,7), (1,2,6), (1,3,5), (1,4,4), (2,2,5), (2,3,4), (3,3,3)

pic probably not related
>>
File: YoungFlip.gif (6KB, 437x450px) Image search: [Google]
YoungFlip.gif
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>>9100698
Partition of a number, N, into exactly 3 parts.

Incidentally the number of ways to do this is the same as the number of partitions of N whose largest part is 3.
>>
>>9100831
>incidentally
Boy you need number theory
>>
Partioning a number n into m parts kan be done in (n-m-1)C(m-1) ways
>>
>>9100930
The picture >>9100831
is proof enough.

>>9100949
That's the answer if the m "parts" are labelled with m different labels.

From OP's example
>6 -> Only 1,2,3
not all 3! permutations (OP is is obviously talking about unlabelled partitions)
>>
>>9100698
6-> (1,2,3), (1,1,4) btw
>>
>>9100960
Shit, I missed that one.
Thread posts: 7
Thread images: 2


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