Can someone please explain question 21. I tried everything to

>>9096969
Use synthetic division/long division.

f(2)=0 implies f(x)=(x-2)g(x) where degree of g is 1 less than f, so g(x)=ax^2+bx+c.
f(x)=(x-2)g(x)
Expand that out, easy to work out what a, b and c are.
Write f(x)=(x-2)(ax^2+bx+c) and I guess you're done.

expand the whole thing out and separate the terms with real coefficient from the terms with imaginary coefficients

>>9097015
>separate the terms
no don't do that because the coefficients are complex

>>9096969
(x-2)(x+1)(x-3i-1)

>Synthetic the first root
>The second one is obvious
>The third one is obvious

Use Horner you mongoloid
>>>/sqt/

>>9097019
I tried synthetic on the first root (x-2). It doesn't divide into c=0

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2MB, 3264x2448px

>>9096969

>>9098112
NB Not OP
Whats your division method? I just did long div in my head n got the same answer as you but I've never seen that kind of compact form before where you've also taken out the factors

>>9098112
This is synthetic division. It is a polynomial division shortcut when the divisor is in the form (x-a)