3 (3^x/2)^2 the answer is 3^x+1 but how do I get there?

>>9083653
>>>/wsr/
or
>>>/sci/stupid

>>9083657
It took you more time to link me to this shit that wont get replies than answering the question. I understand it's a dumb question but you might as well just answer now that you are invested :^)

>>9083660
That's basic algebra properties.
Tips:
> (a^x)^2 = a^(2x)
> (x^a * x^b) = x^(a + b)

>>9083665
wait is it just written differently? I kept getting to 3(3^x) but couldn't that be simplified to get the answer? Jesus Christ I'm a retard.

>>9083678
[eqn] 3 * (\frac{3^x}{2})^2 = 3 * \frac{3^{2x}}{4} = \frac{3^{2x + 1}}{4} [/eqn]

>>9083678
3 * 3^x = 3^1 * 3^x = 3^(1+x)

>>9083688
its not (3^x)/2, its 3^x/2. whatever I think I found my error anyway

>>9083697
yeh that's what I thought. Thanks bro.

>>9083699
>its not (3^x)/2, its 3^x/2.
3^x/2 = 3^x/2
I think you meant then 3^(x/2)

>>9083702
Sorry, 3^x/2 = (3^x)/2