You have a sphere with an hexagonal grid. How many colours do you need such that each cell has a different colour than all its neighbors? In a flat space it's pretty obviously 3, although I have no idea about proofs or geometry.
>>9038206
It's the same as the plane. Just cut a point out of the sphere
You can't have a purely hexagonal grid on a sphere.
>>9038252
>You can't have a purely hexagonal grid on a sphere.
[citation needed]
>>9038257
https://en.wikipedia.org/wiki/Theorema_Egregium
>>9038252
Ok, how can I know which shapes can be made into a grid on a sphere? I know a cube can be deformed into a sphere, so squares can so long as it is 6 of them. I imagine triangles can too.
>>9038374
So only regular polyhedra I suppose.
>>9038382
You can have a grid of 2+ hexagons as long as you include exactly 12 pentagons.
Why do you fucking autists care if the hexagons are regular hexagons? The question presented is about coloring the hexagons.
Btw the answer is 3. 3 in flat space, 3 in curved space. The plane can be mapped onto a sphere. So the answer is as simple as creating an infinite flat plane with all your hexagons, and then putting them on a Riemann sphere with stereographic projection. This is perfectly possible to do with minimal wonkiness. Although admittedly there will be a singularity at one of the sphere's poles that is every color all at once. But this shouldn't be a problem because that singularity also has zero area so no hexagons actually "border" it.
>>9038435
It's not about the hexagons being regular. It's a question about whether the OP means an infinite grid or a finite grid on a sphere.
An infinite grid is dull, because the answer is obvious, and basically what you said.
A finite grid, however can't be done without introducing a some non-hexagonal shape somewhere. So maybe that's the more interesting question. Which I'm guessing you don't have an answer for.
>>9038206
Two. Have you ever seen a soccerball?