Well, /sci/, what is it?

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7

we have been over this before.
many times.

A blue colored triangle.

7. If you can't solve this you are either underage b& or retarded

>>8977741
look mom i posted it again XD

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>>8977741
>Look mom i posted it again XD

>>8977741
There is no answer. Let's say the base of the yellow triangle is "x" and the side of the square is "a". The area of the red triangle gives 0.5a(a-x)=2. The area of the green triangle gives 0.5a(a - 6/x)=4. The solution of these gives a^2 = 44/5. The sum of the three known areas is 9, or 45/5. This is an impossible shape.

>no dimension given nor implied
gtfo fgt pls

>>8977741
Brainlets will say it's 7

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Green triangle gives:
y = 8/a
Red triangle gives:
x = 4/b
Yellow triangle gives:
6 = (a-x)(b-y) = (a - 4/b)(b - 8/a) = ab - 12 + 32/(ab)
(ab)^2 - 18 ab + 32 = 0
ab = 9 +- sqrt(81-32) = 9 +- 7

The area of the blue triangle is:
ab - 4 - 2 - 3 = +-7

>>8977741
Inb4 people assume it's a square cause it looks like one

>this shit again

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7

Does herons formula help?

>>8978565
>not assuming rhombohedral
>assuming perpendicular sides
brainlet confirmed

>>8979059
You left out
>Assuming that the numbers represent units of area

>>8979226
or even
>assuming they represent the same units of area

>>8978254
>This is an impossible shape
Lengths on the boundary are integers

>>8979245
where are teh proofs

>>8979229
>assuming the question is even asking for area

Red = 2
Green = 4
Yellow = 3

Blue + Yellow = Green

Blue + 3 = 4

Blue = 1

They're numbered 2, 3 and 4, so the blue area is 1

>>8978254
not sure how you concluded that the right side of the yellow triangle is 6/x
i don't buy it

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Solved it senpai.

>>8977741
sa/2 = 2
(s-a)b/2 = 3
(s-b)s/2 = 4

s,a,b 3 unknowns 3 equations, go

>>8979544
why can't it be [math]6 * \frac{2}{3}[/math]? Your logic only works on [math]\mathbb{N}[/math]

>>8979494
a friend asked me this question a few days ago
mind if i save your working?
this is groundbreaking stuff

>>8979544
>x>4
>x=4
Anon, you better head down and patent that shit because you just broke math and made billions of $$$.

>>8977741
>What is the blue area?

The blue area is, in the middle.

I feel like it is a square and I feel like the answer will be a whole number.

4+3+2=9
16 is the nearest square of a whole number above 9.

16-9=7

>>8979611
Thank you senpai.

7 seems plausible.

As blue triangle is not quiet the right size and sba0e to allow red to fit in it 4 times. Which would be 8 if it could.

>>8979909
x is greater then y not 4

>>8978254
>The solution of these gives a^2 = 44/5.
This is where you are wrong.

>>8979544
This is a swiss cheese proof.

(Because it has so many holes in it)

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>>8979569
>>8979909
>>8980365
How about this senpaitachi, assuming it is in fact a square?

>>8977741
Assuming it's a square, and the numbers represent areas of other triangles?

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>>8977741
>Overlay area of 4 triangle
>Get half of rectangle, it's equal to 8
>Multiply this by 2
>Get 16
>4x4 = 16
>all areas within square must add up to 16
>4+3+2=9
>16-9=7

>>8977741
Say length of square's side is 4/a. Green triangle's other side is 2a, red's is a.

Solve the equation (4/a - a)(4/a - 2a) = 6 for the answer.

>>8981145
That's a nice thought, but there's no way to decisively prove that the 4 is precisely in the middle.

>>8977741
The question is vague and not mathematical so a person has to assume it's a logic question.

Going by that, the blue area is 1 or 5.

>>8981109
how can you assume the side of the green triangle is twice the side the the red triangle?

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>>8977741
1

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>>8981249

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xy = 1
xz = 2
(x-y)(x-z) = 3/2

additionally x > y and x > z

solving for y and z gives
y = 1/x
z = 2/x

substituting

(x- 1/x)(x - 2/x) = 3/2

solving for x gives either x = 2 or x = sqrt(2)/2, the latter being invalid by our conditions that x>y and x>z

our final dimensions are
x = 2
y = 1/2
z = 1

Since z is exactly half of x, and assuming the shape is a square, the total area is 4 times that of the green triangle, or 16. This gives the area of the blue triangle = 7

>>8981260
Because the green area is twice the size of the red area and they both have a side length of [math]x[/math].

[math]\frac{x \ \cdot \ y}{2}=2[/math]

[math]\frac{x\ \cdot \ 2y}{2}=4[/math]

>>8981284
>Assuming we're dealing with a square

Stop trying to solve it like it's an area mathematics problem ya dumbshits.

If it's not asking you to find THE area OF _______ then it aint geometry.

If it said 'The area of the blue triangle' 'the blue shape' then you could get all retarded with the equations.

If it's just 'What is,' or 'identify_____' then it's a logic problem.

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>>8981259
if this is really a logic question, then the correct answer could be also just "triangle".

>>8981298
Yes, as I said here: >>8981109

>assuming it is in fact a square

>>8977741
A triangle you retard

>>8981310
If the other shapes weren't numbered, then yes. Since they are, then you have to assume your expected to find a common pattern. 1 is the most likely answer, but since we can also apply the same pattern to 5, we include it.

>>8981325
can't argue with that

>>8981311
Or even assuming right angles.

>>8978586
Assumes the right side of the green and yellow triangle are of equal lengths.

Fold over 2 & 4. It's 6
If it's not. Fuck you.

-1/12

>>8983031
No it doesn't, you tard.

He made rectangles from each tighttriangle so he could find the total area of the square. Then he subtracted the given area.

I'm not even a regular here. My goodness. I hope you aren't either.

>>8977741
>>>/his/

i've got 7.25

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>>8983725
The bottom left rectangle will not have the area of the red triangle unless the right side of the green and yellow triangle are of equal lengths.