[math]frac{a}{b}[/math]
\frac{a}{b}
[math] \frac{a}{b} [/math]
[math]\frac{a}{b}[/math]
[math]
B =
\begin{matrix}
\lambda_1 & 1 & 0 \\
0 & \lambda_1 & 0 \\
0 & 0 & \lambda_2
\end{matrix}
[/math]
>>8976917
[math]B = \left( \begin{matrix} \lambda_1 & 1 & 0 \\ 0 & \lambda_1 & 0 \\ 0 & 0 & \lambda_2 \end{matrix} \right)[/math]
here you go senpai
[math] \frac{1}{a^2-x^2}=\frac{1}{2a}(\frac{1}{a+x}+\frac{1}{a-x}) [/math]
Use the relation [math] \frac{1}{a^2-x^2}=\frac{1}{2a}(\frac{1}{a+x}+\frac{1}{a-x}) [/math] to find the nth derivative of [math] \frac{1}{a^2-x^2} [/math]
Solution: [math] \frac{n!}{2a}(\frac{1}{(a-x)^{n+1}}+\frac{(-1)^n}{(a+x)^{n+1}}) [/math]
How is this found?
>>8976906
>
There's a compiler button at the top left of the Quick Reply box so you can test out TEX commands without actually having to post.
cheer up depressed quartic
always rember
>>8976966
>k
Thanks anon and sorry for the thread