2cos(πx)=cos(πx) 0<x<3 What is it /sci/?

Stop cheating on your SAT faggot

>>8954653
no u

You tell me

>>8954644
-1-1-1-1-1-1-...

>>8954644
Pull up the weiner burger, say cosine isn't real and go do the next problem

it's [math]\frac{\pi}{2}[/math] anon

>>8954749
shit, made a mistake responding to a bait thread, what a shame
it's a half, duh

>>8954644
>divide both sides by cos(πx)
>2=1
Math fags BTFO

>>8954644
1
2cos(pi*1)=cos(pi*1)
cos(npi)=0 where n is an integer
2*0=0
True
*)

>>8954644
Easy peasy, here's a real question for /sci/.

x > cos(π/4) where x is the real part of a solution to ζ(s) = 0. What is s?

>>8954644
Learn 2 [math]\TeX[/math]

>>8954768
except when cos(pi*x) = 0, then you can't divide. You're starting to understand this maths stuff, congratulations. Now find all x where cos(pi*x) = 0

[math]
2 \cdot cos(π \cdot x) = cos(π \cdot x)
[/math]

can only be true if [math]cos(π \cdot x) =
0[/math]

And looking at a simply cos graph, you'll notice that [math] cos(a) = 0 [/math] whenever [math] a = \frac{(2 \cdot k - 1) \cdot π}{2} [/math] for some integer [math] k [/math]

So:
[math]
π \cdot x = a = \frac{(2 \cdot k - 1) \cdot π}{2}

x = \frac{2 \cdot k - 1}{2} [/math] for some integer [math] k [/math]

And since [math] 0 < x < 3 [/math]

Then [math] x = \frac{1}{2} or x = \frac{3}{2} [/math]

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>>8955036
Math.
Fags.
B.
T.
F.
O.

>>8955410
X^2=y^2 doesn't mean that x=y

>>8955129
You forgot 5/2, brainlet.

>>8954833
answer is trivial; post this in stupid questions thread

>>8955036
>>8955415
I wonder if it ever went through your head that those posts are jokes and you just thought it was unlikely enough that you had to make these posts, or you're just so autistic that you don't quite understand what a joke is.

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>>8955648
I just wanted validation from anons to feel like a non brainlet