Solve this because it's what you were built to do

>>8927543

(9x - 5) / (6x-6) = 25/15

3/2 + 2/(3 (x-1)) = 5/3

x = 5

middle school math lol
do it yourself

>>8927543
are taking some kind of remedial middle school geometry in college for some reason or are actually underaged

either way the answer is x=5

What class are you taking?

>tfw i don't know how to do this

>>8927909
I believe this explains it:
https://www.youtube.com/watch?v=Z5EnuVJawmY

>>8927569
(9x - 5) / (6x-6) => 3/2 + 2/(3 (x-1))

what?

File: 1406942749630s.jpg (3KB, 102x125px) Image search: [Google]

3KB, 102x125px

>>8927543
>tfw i was able to solve this
I guess my math degree paid off after all

>>8927543
draw a line perpendicular to the three parallel lines. Now, take the orthogonal projection of the line segment of length 25 onto this new center line. Now, take the orthogonal projection of the line segment of length 15 onto said line. The line segments are just vectors with different magnitudes, but the same direction, so the length the project onto the center line must depend only on the magnitude of the line segments. Hence, the orthogonal projection of the 25 line segment is 5/3 as long as the orthogonal projection of the 15 line segment. Now, we can apply the same logic to the 9x - 5 line segment, and the 6x - 6 line segment. So, the orthogonal projection of the 9x - 5 line segment must be (9x - 5)/(6x - 6) the length of the orthogonal projection of the 6x - 6 line segment onto the line. So A = (5/3)*B, and A = (9x - 5)*B/(6x - 6), so (5/3)*B = (9x - 5)*B/(6x-6), and 5/3 = (9x - 5)/(6x - 6). So 10x - 10 = 9x - 5, x = 5.

File: easy.png (7KB, 585x547px) Image search: [Google]

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sec(theta) = (9x-5) / 25 = (6x-6)/15

>>8927543
dude they are just lines wtf are u stupid?