What is the integral of position? I know the integral of Acceleration is Velocity, and the integral of Velocity is position, but what is the integral of position?
>>8877145
cal 1 brainlet here btw
>>8877145
Source on that gif?
>>8877145
absition
>>8877158
no idea man. found it on here. this is the closest i got
http://rebloggy.com/post/gif-computer-girl-sad-anime-rain-pixel-art-pixel-pixels/72332710036
What do you mean? There is not integral of position. If you're talking about position as a function of time then that integral is something called absement.
>>8877197
yea. that's what i meant. is absement just the total displacement?
>>8877145
With respect to time?
it has no meaningful physical sense, since by integrating you pick up an arbitrary constant
>>8877206
yes
>>8877207
>what are initial conditions
>>8877145
depends what you put on the vertical axis
>>8877207
why does it not have any meaningful physical sense?
>>8877196
Thank you, I'm now having great trouble sourcing it. I must find the artist!
>>8877203
No. That would be distance. Absement is a measure of displacement for a certain period of time. E.G. If an object is at a constant distance from your frame of reference and is not moving as time goes by, the graph of absement vs time is the graph of a straight line with a slope equal to the displacement. If the object starts moving at a constant speed then the graph would look like a quadratic equation.
Just read the wikipedia page for more info.
https://en.wikipedia.org/wiki/Absement
it's the average position times the length of the time interval
>>8877145
Integrating acceleration means adding up the acceleration at smaller and smaller intervals until the delta time approaches zero. So if your acceleration is something like:
[math]a = 5[/math]
then your velocity is a line with slope 5 or you can say it's a value that increases by 5 units per one unit of time.
[math]v = 5t[/math]
Integrating velocity means adding up velocities, similarly, so if your velocity is a line with slope 2, then your position is a curve (parabola) that increases by zero at time zero, by 2 at time 1, by 4 at time 2, etc... So the amount of the increase is increasing.
[math]p = \frac{5t^2}{2}[/math]
Adding up your position over time would give you a cubic curve, but what physical meaning does the sum of position have? Say a rock is sitting motionless on the X axis at
[math]p = 5[/math]
Integrating that would give you a line with slope 5, but there's no physical meaning to attach to that. You're saying "something about this rock is changing at a rate of 5 units per second" when really the rock isn't doing anything.
>>8877244
Sorry if this is a stupid question, but what if the rocks position was changing?
>>8877244
You can think of it as an aggregate of the positions the rock takes over a certain period of time.
Think of it like this. Say there is a spring attached to the rock, and that it's displacement from a point p (let's say the other end of the spring is attached to p) over a certain time is caused by you pulling the rock away from the point p. The absement, or time integral of position, would be how tired you get after a certain period of time. The further you pull away the rock, the quicker you become tired (hooke's law). As time goes on you get more tired, with tiredness as a straight line with the slope being the displacement.
>>8877145
Don't you mean Derivative?
I thought the Derivative of acceleration was velocity
>>8877145
Area covered