[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y ] [Search | Free Show | Home]

∞ * 0

This is a blue board which means that it's for everybody (Safe For Work content only). If you see any adult content, please report it.

Thread replies: 16
Thread images: 2

Trying to determine this LIM, but i cant seem to go aroung ∞ * 0. Anyone has any ideas?
>>
>>8846817
Tip:
[math]e^\alpha = \frac{1}{e^{-\alpha}}[/math]
>>
You should have learned this in highschool but I guess you actually dont know what to do.

Search for "rule of l'hospital" and you should be able to figure out the rest.
>>
Exponentials beat polynomials
>>
>>8846831
Im in highschool, my teachers hasnt touched this subject. She's pretty old, doesnt have the teaching capabilitiies she once had
>>
It suffices to show that after one point on the negative axis, [math] \alpha \cdot e^{\alpha} [/math] is squeezed in between the zero line and [math] \frac{1}{\alpha} [/math]

i.e

[math] \alpha \cdot e^{\alpha} > \frac{1}{\alpha} [/math]

i.e.

[math] \alpha^2 \cdot e^{\alpha} < 1 [/math]

In reality this even holds on the whole negative axis.
>>
>>8846833
Did you look up l'Hospital?

Also if youre underage b& please do get off this site. Wether you see it or not, you are bringing down what little quality this board has left.
>>
>>8846840
And that's true because the function has a global maximum on that interval, at [math]\alpha=-2[/math],
where it evaluates to
[math] 4 e^{-2} < 1 [/math]
>>
>>8846831
to be fair, sometimes highschools / unis want their students to solve certain limits without the l'hospital rule in order for them to grasp the principles of limits better.
then it introduces that rule after a few weeks or so, to then move on to more difficult problems
>>
File: 1492827298874.gif (569KB, 362x366px) Image search: [Google]
1492827298874.gif
569KB, 362x366px
>>8846817
USE L'HÔPITAL

[eqn]
\lim\limits_{\alpha \rightarrow -\infty} \alpha e^\alpha = \lim\limits_{\alpha \rightarrow -\infty} \frac{\partial}{\partial \alpha}\frac{\alpha}{e^{-\alpha}} = \lim\limits_{\alpha \rightarrow -\infty}\frac{1}{e^{-\alpha}} = 0
[/eqn]
>>
>>8846870
then your teacher most likely wants you to solve the problem without it, it's more of an intuitive question.
>>
>>8846817
https://math.stackexchange.com/questions/767781/why-does-lim-limits-t-to-inftytet-0
there's a proof at the bottom
>>
>>8846817
Looks like an L not an e.

Lim alpha * e^alpha =
Lim alpha * Lim e^alpha
= 0 * infinity = 0
>>
>>8846921
dude infinity isn't element of the real numbers
>>
>>8846921
>0 * infinity = 0
No.
>>
>>8846924
>>8847328
I know you can't actually break them up like that, but I doubt op knows how to do delta epsilon proofs.
Thread posts: 16
Thread images: 2


[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y] [Search | Top | Home]

I'm aware that Imgur.com will stop allowing adult images since 15th of May. I'm taking actions to backup as much data as possible.
Read more on this topic here - https://archived.moe/talk/thread/1694/


If you need a post removed click on it's [Report] button and follow the instruction.
DMCA Content Takedown via dmca.com
All images are hosted on imgur.com.
If you like this website please support us by donating with Bitcoins at 16mKtbZiwW52BLkibtCr8jUg2KVUMTxVQ5
All trademarks and copyrights on this page are owned by their respective parties.
Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
This is a 4chan archive - all of the content originated from that site.
This means that RandomArchive shows their content, archived.
If you need information for a Poster - contact them.