prove to me that 0.999... does not equal 1
>>8840612
Wouldn't that imply that .000... = 0?
>>8840612
Do people that constantly make these threads just have never been through calculus? Not understand convergence?
>>8840633
op here
i do believe that 0.999... = 1
but im curious to see people try to disprove it
>>8840617
>implying proof by contradiction is valid
You literally posted an algebraic proof of it as your image, don't pretend this wasn't a clickbait thread for (you)s.
Prove to me that it does without using erroneous approximations of fractions.
>>8840658
You might as well ask me to prove it using toothpicks
>>8840658
What is 0.999... + 0.111...?
>>8840678
1.1 repeating
>>8840701
What happens when you subtract 1 from that?
>>8840706
same thing as subtracting 0.999...
you get 0.111...
>a number with infinite significant figures has the same value as one with one significant figure
>people actually believe this
>>8840658
I'm going to take the bait.
1. If you accept the properties of real numbers then you are forced to accept that .999...=1. Why? Because there is no number between .999... and 1.
2. Convergence of geometric series.
3. The supremum and infimum of .999... are both 1. But this is impossible unless .999... = 1.
Fuck you. I hate the use of the word brainlet in pretty much any context, but anyone who claims that .999...!= 1 is an actual, true to life fucking brainlet.
>>8840637
You are what's wrong with /sci/. Can't we clean this board up a bit, please?
So 9.999999....=10 ?
>>8841126
9.99...=9+0.99...=9+1=10
Did you even need to ask?
>>8840612
does 999=1000?
>>8841198
No, but 999.999..=1000
Does that mean 3.1415...99999... = pi?
So the square root of .9999999999...
Equals the square root of 1?
>>8840612
(1-0.99...) = 0.000..1
(1-0.99...) + (1-0.99...) = 0.00...2
0.00...2 * inf = 2
but if 0.999... == 1 then
(1-0.99...) = 0
(1-0.99...) + (1-0.99...) = 0
0.00...2 * inf = 0
>>8841256
>0.00...2 * inf = 0
should be 0 * inf = 0
>>8841116
Can we just add the fraction proof to this and make this an automated answer for these threads so we can shut them down immediately?
>>8840612
suppose [math]0.\overline{9}=1[/math]. then let [math]\epsilon>0[/math]. if [math]0.\overline{9}+\epsilon=1[/math], then [math]\epsilon=0[/math]. but [math]\epsilon>0[/math], which is a contradiction.