if lambda equals 1/50 (flaws per yards) and 50 yards inspected, what is the probability that the number of yards that have one or more flaws is fewer than or equal to 2?
My problem here is not how to do it, but whether I include 0 or not. I'm using a poisson distribution
>>8819778
Lolz poisson means fish in French so nerdy xD
>>8819791
such insightful help
>>8819778
I think you need to include the yards that have 0 flaws in your analysis. Pr(X=0)+...+P(X=2)=P(X<=2) if I am not retarded.
If this is not enough maybe I misunderstood something.
>>8819778
So much for a board for math and science. What a useless board.
>>8819829
Is there a deeper explanation, because I still can't see the justification. Because it clearly states number of yards that have one or more.
>>8819834
There is a deeper explanation. Pr(X=n) is read as "the probability that the random variable X is equal to n".
I assumed that your random variable stood for the number of yards that have at least one flaw. Please let us note that if your poisson distribution is a model for the number of yards that are flawed then this analysis is not adequate.
When I took probability one of the books we used was Ross introduction book on probability. It covered the practical stuff, so it may be appropiate for this situation.
>>8819854
therefore 0 is not included?
>>8819868
In order to know the probability that there are at most 2 flawed yards we need to add the probabilities of there being 0,1 and 2 flawed yards. If you are assuming this process follows a Poisson distribution then the above should hold, therefore 0 should be included.
>>8819912
I appreciate it. It makes more sense now.
What has fish to do with poison? Are so many fish poisoned?
>>8819995
Yes