prove me wrong

>>8756513
.999.... = x
10x = 9.999...
10x - x = 9.999... - 999...
9x = 9
x = 1

op is right

>>8756513
I don't think anyone would disagree...

>>8756513
Nope.
x = .000....1
1 - x != 1

>>8756513
1-0.999...=0.111...=/= 0

>>8756559
>actual retard

>>8756559
lol wat
1.00000000000
0.99999999999
-____________

Here's a subtraction table. Subtract the
decimals like you would in preschool.
>hint .11111 isn't the answer

>>8756559
but 1-0.999...=/=0.111... idiot

1/9=0.11111....
9*1/9=0.99999....
9/9=1=0.99999....
Another simple proof

>>8756554
faggot
numbers like .000...1 don't exist.

to all the retards,
think of it like this.
You cut a pie into thirds.
Each slice is .333... of a pie.
All three slices = .333...+.333...+.333... = .999...
It's still a whole pie.
therefore .999...=1

>>8756554
0.000...1 would be like the inverse of infinity, so it tends to 0.

>>8756586
the 1 on the end makes it impossible for it to be zero

>>8756513
Let 's say I have a jar and that jar has to be filled 100% with marbles for it to be heavy enough to move the piston down where it stands on.
The jar can be filled with 50000 marbles.
In the process I lose 1 marble to an anon who is walking by and thinks it is funny to steal 1 marble.
I will never move the piston.
0.99999 is not 1, you are short a tiny fraction.

>>8756757
except 1/50000 is a countable fraction
1/∞ makes it impossible to not move the piston

>>8756718
the infinite zeros quite obviously overpower the one. do you really think that [math]\infty[/math] and 0 are less powerful than an infinitesimal 1?

>>8756718
There can't be a 1 on the end because there is no end.

>>8756757
Okay, so that jar has to be completely full.
as in 9/9 full.
1/9 is .111...
2/9 is .222...
etc.
9/9 is .999...
9/9 = 1

>>8756513
props for using a cia meme

>>8756785
story?

>>8756792
Bassically when wikileaks released Vault 7,
included in the conversations between CIA
employees were memes. A fuck ton of them.
every documented meme (that I know of) can be found:
https://ciamemes.neocities.org/memes.html

>>8756774
Nope, if the marbles used each have a weight of 1000 kg, 1 missing would make difference big enough.

>>8756800
yeah ding dong but there's only 50k marbles in your theoretical example. If we're talking about a relationship between .999... and 1, it would be more like ∞ marbles and you take away one.

>>8756757
give me an algebreic proof faggot. words let you make shit up.

>>8756776
an infinitesimal 1 is still an infinitesimal 1.
It doesn't change the fact that it's not completely
zero.

File: Twister-Youre-doing-it-wrong.jpg (56KB, 480x720px) Image search: [Google]

56KB, 480x720px

>>8756780
9/9=0.9999
10/9=1/9+9/9=0.1111+0.9999
by the logic you are using
9/9 is not even 1.

>>8756854
>10/9=1
no, retard, 10/9 = 1.1111...
try not being retarded

File: Third-World-Success-Kid.jpg (28KB, 500x500px) Image search: [Google]

28KB, 500x500px

>>8756513
I did. And you can't have it.

0.9 = 9/10
(9(10^(-a-1) - 1)) / (10(10^(-1) - 1)) // 10^1 * 10^(-1) = 10^0 = 1
= (-9(10^(-a-1) - 1)) / (9) // (9)s cancel out
= -(10^(-a-1) - 1)
= 1 - 10^(-a-1)
Lim a->infinity, substitute infinity to get the value
= 1 - 10^(-i-1)
= 1 - 10^(-i) // negative infinity subtract a number is negative infinity
= 1 - (10 / i)
= 1 - (1 / i)
Can we agree that
Lim a->infinity = 1 - (1 / i)
All I did was simplify the equation by elimination, so there's nothing changed.
Assume,
0.9r = 1
(I write 0.9 repeated as 0.9r)
The use of geometric progression is the only way to write 0.9r.
Therefore
1 - (1 / i) = .9r
Agree? Ok.
.9r = 1
.9r = 1 - (1 / i)
1 - (1 / i) = 1
1 / i = 0
FALSE. Division by infinity DOES NOT EQUAL ZERO. It's an infintesimally small number, NOT ZERO.
THEREFORE 0.9r CANNOT EQUAL 1