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a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a+b)(a-b) = b(a-b)
a+b = b
2b = b
2 = 1
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a=b=0
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>>8725230
a-b=0 so you can't divide by it
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https://www.math.toronto.edu/mathnet/falseProofs/first1eq2.html
Here's to hoping this was a troll.
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This proof is known as a (false proof) because of it's seemingly acceptable outcome.
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>>8725236
a - b = 0 by assumption which means you can't divide by it. However we can easily get around that by making the proof into one where a --> b.
What's your response now?
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Fourth row is 2*0 = 1*0
Nothing makes sense below the fourth row
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>>8725251
Kek
You sure showed him!
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>>8725265
I'm not sure if you're being sarcastic or not. This problem is trivial, but if you turn it into a limit problem it's suddenly not so clear where the wrong step is.
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>>8725278
I think it's clear what's wrong with it. It just doesn't logically follow from the line before.
I guess I see what you mean, but really you don't need to look for something "wrong" with a step. You have to justify what's right about it.
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>>8725276
If a --> b, then a=b is not necessarily true.
Consider epsilon greater than 0, is never equal to 0 but in almost all limit questions we try to make it approach 0.
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>>8725312
a = b + e
a^2 = a(b+e)
a^2 - b^2 = ab - b^2 + ae
(a+b)(a-b) = b(a-b) + ae
a + b = b + ae/(a-b)
a + b = b + a
Oh, I guess you're right. My b senpai
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>>8725251
so 1 -> 2?
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>>8725230
You said a=b, so when you divided by a-b, you divided by 0.
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>>8725230
line 5 contradicts line 1
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>>8725448
WOW GIVE THIS MAN A NOBEL PRIZE
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>>8725230
Brainlet divides the fucking variable.
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