95% of you will fail

>>8724447
damn, tough one.
guess it's something with arcsin (because of the form), but I don't have the patience to start substituting integrals.

>>8724447
Nice try. We won't do your homework, cunt.

>>8724447
>>>/hm/
Homework board is this way friendo

>>8724447
The amount of effort you put into this homework post is impressive, I'll say that.

>>8724465
>>8724477
>brainlets spotted who are omitting a cry of help because they started the problem and realized it's too hard for them so they project their insecurities onto the alpha who put them in this conundrum

wew lad

>>8724447
The indefinite integral of f(x) is:

F(x)=ln(tan(arcsin(x)-1))-(5/8)ln(tan^2(arcsin(x))+1)-(1/2)arcsin(x)+c

Next time give me something less easy ;)

>>8724510
Cleo pls

>>8724497
>omitting a cry of help
>omitting
Looks like a brainlet is you

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66KB, 554x400px

You can't answer it, you never specified what to compute the integral in respect to.

>>8724447
>indefinite integral

That isn't a thing. Made up notion taught in brainlet tier calc courses.

>>8724680
Are you claiming antiderivatives aren't real math? Care to back up that claim?

>>8724510
When you differentiate your result you don't get the original function. How does it feel to be this wrong?

>>8724700
There is no inverse to the derivative operator. Finding antiderivatives is just an adhoc system of calculation tools and is in general an ill-defined notion.

And "indefinite integral" is just a flat out horrible abuse of terminology.

1 over x fuckface

>>8724752
>no inverse to the derivative operator
???

>>8724447
(log(-1 + sqrt(5) - 2 x) - log(1 + sqrt(5) + 2 x))/sqrt(5)

now fuck off cunt

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214KB, 960x960px

1/4 (-2 sin^(-1)(x) - 2 tanh^(-1)(x/sqrt(1 - x^2)) + ln(1 - 2 x^2))

>>8724680
You sure didn't pay attention to calc.

>>8724680
http://tutorial.math.lamar.edu/Classes/CalcI/IndefiniteIntegrals.aspx

study hard brainlet

>>8724752
lmaooooo

>>8724769
There is no inverse to the derivative operator.

>>8724791
Calc classes are horrible excuses for mathematics

>>8724794
That "definition" is not at all rigorous

>>8724812
>There is no inverse to the derivative operator.
There is if you consider functions modulo an added constant. Don't be such a butthurt faggot