Is my calculator wrong?!
How can cos^2(x) - sin^2(x) be equal to (cos^2(2x)) - 1 when the double angle trig identity states: cos^2(x) - sin^2(x) = cos(2x)
Explain this to me /sci/
learn to read retard
>>8720435
cos^2(x)+sin^2(x)=1
cos^2(x)-1= -sin^2(x)
now substitute
into your trig identity
cos^2(x)-sin^2(x)=cos(2x)
2cos^2(x)-1=cos(2x)
>>8720438
Thank you for the thorough explanation.
>>8720435
Lmao, trying to cheat on your precalc test. Nice.
Besides the fact that you have to be a massive faggot to buy a calculator so you can more effectively cheat, you'll regret not learning your trig identities in calculus.
>>8720452
>cos^2(x)-sin^2(x)=cos(2x)
What trig identity are you using to substitute?
>2cos^2(x)-1=cos(2x)
I still don't understand how you get rid of the -1
I get that 2cos^2(x) = cos^2(2x) , but how does the -1 cancel out?
>>8720435
Are you the middle school brainlet from earlier who dropped out of business to study physics?
>>8720487
nope
>>8720477
>you'll regret not learning your trig identities in calculus.
I'm currently in Calculus now, the reason it says pre-calc at the top of the screen is because I have a tab with all of the identities written out for reference.
I know
cos(2x) = cos^2(x) – sin^2(x) = 1 – 2 sin^2(x) = 2 cos^2(x) – 1
because the double angle identity says so, but I don't understand why how one would come to such a conclusion mathmatically
>>8720510
there is a proof of the double angle identities. its geometric, look it up on khan academy
>>8720553
>>8720477
I remember in high school we automatically lost marks on tests if we walked into an exam room without a calculator.
>>8720575
Thanks mate!