Hi, can someone please help me with this problem. I've spent tons of hours trying to formulate a solution but it's of no use. The assignment is meant to be easy but it poses a challenge for me. You should use the law of sines and the law of cosine on this one. Please help, much appreciated! Thank you in advance. PS. This isn't homework.
? = 210*sin(70°) + 150*sin(70°+(130°-180°)) + 125*sin(70°+(130°-180°)+(120°-180°))
>>8679806
False answer, the heck. XD. Never Mind, problem isn't meant for anyone except the elite.
>>8679747
sine - a/sina = b/sinb = c/sinc then the inverse for angles.
I'm a fucking brainlet too though.
152.8829
that last angle is 50 degrees not 40
>>8680221
in pic where i say 'angle between f and CD'
should be 'angle between e and CD' sorry, but you get what you pay for :D
not using autodesk inventor to solve trivialities
why even live...
>>8680893
here is the solution
>>8680896
solution yes, but the thought process behind it?
The solution to the assignment you guys proposed, 168(.29) , was correct. Thank You!
>>8679747
heres a hint
>>8679747
calling it an assignment doesn't mean it's not homework
>>8679857
That solution is correct, you are just a retard.
>>8681899
http://www.wolframalpha.com/input/?i=210*sin(70%C2%B0)+%2B+150*sin(70%C2%B0%2B(130%C2%B0-180%C2%B0))+%2B+125*sin(70%C2%B0%2B(130%C2%B0-180%C2%B0)%2B(120%C2%B0-180%C2%B0))
yep
>>8679747
>>8679747
One step at a time. Keep filling in missing angles and lengths until you reach the final triangle. Do not calculate results until the end; the earlier you calculate sin's and cosine's the more inaccurate the final answer (e.g. you might be able to cancel out). There is 180 degrees in triangles. Giving you the answer is meaningless unless you're asking for confirmation of the answer you calculated.