[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y ] [Search | Free Show | Home]

Maths Help

This is a blue board which means that it's for everybody (Safe For Work content only). If you see any adult content, please report it.

Thread replies: 18
Thread images: 5

File: q9.png (7KB, 385x271px) Image search: [Google]
q9.png
7KB, 385x271px
Hey /sci/

can you help with some maths please? There are 3 questions I'm really stuck on.
Here is the first one. I'm getting an answer of 60 degrees but it's not on the list of options, so I don't know wtf I'm doing wrong. I'll post my working after.
Help appreciated.
>>
File: DCIM_00391.jpg (47KB, 540x960px) Image search: [Google]
DCIM_00391.jpg
47KB, 540x960px
Is the answer 0.8660 or -0.8660 ?
>>
And second question, a bit simpler, but how the fuck do I make this into a diagram?

" Draw a diagram (including the unit circle) which shows that cos(-Θ°)=cosΘ° "
>>
Its asking for sin theta not theta.
If costheta is 0.5 costheta squared is 0.25
1-0.25 = sintheta squared.
0.75 = sintheta squared
Answer is sqr root of 0.75 which is +- 0.8660
>>
>>8630199
Thank you!
I got to 0.8660 in my working, does sin^-1 make the answer +-0.8660 ?
>>
>>8630199
Wrong.

Every real number has 1 and only 1 square root. It is also always greater than or equal to 0.
>>
>>8630204
So 25=5^2 , but not 25=(-5)^2 ?
>>
File: q8.png (17KB, 427x434px) Image search: [Google]
q8.png
17KB, 427x434px
>>8630193
is something like this an acceptable response?
>>
>>8630204
What?
>>
>>8630193
Draw a unit circle (radius of 1)

Now draw an arbitrary angle. It will be easier to see if you draw the angle in the first quadrant of that circle. Label that angle [math]\theta[/math]
Now draw [math]-\theta[/math], which just means draw the same angle except it's clockwise from the horizontal rather than counterclockwise. You are now aware that [math]\cos{\theta} = \cos{{-\theta}}[/math], since cosine is the horizontal part of the right triangle which forms on the unit circle.

>>8630209
I would not use an angle of 0, since obviously +- 0 are actually the same angle. Choose something less than greater 0 and less than 90 degrees for simplicity.
>>
>>8630202
No its +- because a positive numbers square root can be positive or negative.
E.g 25 = 5 × 5 and 25 = -5 x -5
So square root of 25 is +- 5
>>
>>8630217
>Choose something less than greater 0 and less than 90 degrees for simplicity.

Typo. Meant to say choose an angle [math]0^\circ < \theta < 90^\circ[/math]
>>
File: q8 revised.png (24KB, 363x427px) Image search: [Google]
q8 revised.png
24KB, 363x427px
>>8630223
>>8630217

OK what about this?
>>
>>8630227
Good, just draw an angle of -45 degrees now. You will see that the two triangles share a common side on the x-axis. Since cosine(theta) = adjacent/hypotenus, and the adjacent sides of both angle are equal, and the hypotenus is equal, it's clear that cos(theta) = cos(-theta) = adjacent/hypotenus
>>
>>8630227

Haha. You are so close. The triangle you drew is theta. Now you should draw one for negative theta in the 4th quadrant.
>>
File: q8 revised2.png (27KB, 363x427px) Image search: [Google]
q8 revised2.png
27KB, 363x427px
>>8630235
>>8630231
am I retarded or is this correct?
>>
>>8630239
Yes, but you should label the angles.
>>
>>8630208
>>8630215
Square root specifically means a function that returns a positive 2nd order root.

I never said a negative number squared isn't positive.

Every polynomial degree 2 has 2 roots but the square root is a function that only returns the positive. Look it up.
Thread posts: 18
Thread images: 5


[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y] [Search | Top | Home]

I'm aware that Imgur.com will stop allowing adult images since 15th of May. I'm taking actions to backup as much data as possible.
Read more on this topic here - https://archived.moe/talk/thread/1694/


If you need a post removed click on it's [Report] button and follow the instruction.
DMCA Content Takedown via dmca.com
All images are hosted on imgur.com.
If you like this website please support us by donating with Bitcoins at 16mKtbZiwW52BLkibtCr8jUg2KVUMTxVQ5
All trademarks and copyrights on this page are owned by their respective parties.
Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
This is a 4chan archive - all of the content originated from that site.
This means that RandomArchive shows their content, archived.
If you need information for a Poster - contact them.