Thread replies: 10
Thread images: 2
Thread images: 2
You guys seem like you can help me...
I sat on a workshop today at work.We returned from a break we began began talking about random facts - I brought up the Birthday Problem/Paradox and we decided we'd test it on our group. (Only 10 of us including the tutor).
The first person said their birthday was the 17th October and got a match in the room. The second was 27th June and also got a match in the room.
I'm terrible at math, but would someone be so kind of enough to calculate the probability that in a group of 10 people, if the first two people shared their birthdays they would both find one matching birthday in the group? What about if there was a third match?
I hope this is a simple calculation (sorry if not).
>>
>>8612045
the answer
is 4
>>
>>8612045
have you read the wikipedia article for the birthday problem? it should probably allow you to do the calculations.
>>
>>8612049
As satisfying as I'm sure calculating this myself would be it's beyond my capability. Math isn't something I'm competent at.
I was hoping someone might provide an answer and get a bit enjoyment out of doing so!
>>
Bumperino
>>
According to wikipedia:
p(10) = 1 - (10!*355C10)/365^10
p(10) = 0.116948177
so like 11.7%
also pic related from the article
>>
>>8612045
wait but you said FIRST TWO so i think you would the binomial distribution
>>
>>8612167
Yeah, the first two both getting a match in a group of 10. :)
>>
It has to be the first two not matching each other, then both finding a match from the other 8? Or just 2 sets of people both sharing bdays?
>>
>>8612440
That's correct. The first two people finding matches from the other 8.
Thread posts: 10
Thread images: 2
Thread images: 2