Norton Equivalents

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Anonymous
Norton Equivalents 2017-01-12 09:31:04 Post No. 8596171
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Norton Equivalents Anonymous 2017-01-12 09:31:04 Post No. 8596171 [Report]

I am trying to convert the top circuit to a Norton Equivalent, and cant and I am always 100mA out in calculating it. I know Is/c has to be 5A but i can't get closer than 5.1

Any help Sci

Anonymous 2017-01-12 10:01:53 Post No.8596198
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Anonymous 2017-01-12 10:01:53 Post No.8596198 [Report]

>>8596171
OC voltage B is at 5V, A is at 225V so Vab=220
Input resistance is just 45Ohms

It = Vab/Rab = 220/45 = 4+8/9 Amps

Anonymous 2017-01-12 10:18:49 Post No.8596215
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Anonymous 2017-01-12 10:18:49 Post No.8596215 [Report]

thank you ill try that.

Anonymous 2017-01-12 10:30:29 Post No.8596222
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Anonymous 2017-01-12 10:30:29 Post No.8596222 [Report]

oh fuck, i already had that answer 2 hours ago. Brain fart. just found it in my notes.

Anonymous 2017-01-12 11:45:38 Post No.8596310
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Anonymous 2017-01-12 11:45:38 Post No.8596310 [Report]

What does that meter symbol stand for?

Anonymous 2017-01-12 12:23:37 Post No.8596339
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Anonymous 2017-01-12 12:23:37 Post No.8596339 [Report]

>>8596310
current at that path I guess, looks like a simulator

To solve OP's problem I would ignore R4 and R3, convert I1 R2 to a voltage source with 225V in series with 45Ω, then subtract the 5V and get 220V in series with 45+50=95Ω. The resulting minimum equivalent circuit is a single (220/95)=(44/19)A current source in parallel with R1=50Ω. If you want another 45Ω in parallel you have to add (44/19)*(50/45)A to the source current which means you would need (44/9)A.

Norton Equivalents

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